How much bigger is a 42 inch tv that a 20 inch tv, and how do you numeral it?

I belive the 20" measurements are diagonal, so it's not a straight square (and I can't measure the tv sides). Any math majors out nearby?


Answers:    20 inch tvs tend to have aspect ratio (Width to height) of 4:3 whereas most flatscreen TVs have a 16:9 aspect rato.

This is a short time ago simple trigonometry.

The 20" tv has a eyeshade whose diagonal represents the hypotenuse of a classic 3-4-5 triangle. So divide the length of the hypotenuse by 5 (=4) and multiply this by the 4 for the size (16") and 3 for the height (12").

For the 42" TV, assuming a length to thickness ratio of 16:9, the formula of hypotenuse = square root of (16 squared + 9 squared) = 18.36 .

Divide 42" by 18.36 = 2.29. Use this value times 16 to acquire the width (36") and times 9 to bring the height (20").

This is merely the screen comparison; the chassis of the set will incorporate to the dimensions.
I don't understand your sound out that well but you device tv size diagonally and only benchmark screen size not the plastic around the peak.

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